(2x^2+3x-20)/(x-2)

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Solution for (2x^2+3x-20)/(x-2) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(2*x^2+3*x-20)/(x-2) = 0

2*x^2+3*x-20 = 0

2*x^2+3*x-20 = 0

DELTA = 3^2-(-20*2*4)

DELTA = 169

DELTA > 0

x = (169^(1/2)-3)/(2*2) or x = (-169^(1/2)-3)/(2*2)

x = 5/2 or x = -4

(x+4)*(x-5/2) = 0

((x+4)*(x-5/2))/(x-2) = 0

( x+4 )

x+4 = 0 // - 4

x = -4

( x-5/2 )

x-5/2 = 0 // + 5/2

x = 5/2

x in { -4, 5/2 }

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